(1/t)^2-(2t^2-)-2=0

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Solution for (1/t)^2-(2t^2-)-2=0 equation: 



(1/t)^2-(2t^2-)-2=0



Domain of the equation: t)^2!=0

t!=0/1

t!=0

t∈R



We add all the numbers together, and all the variables

(+1/t)^2-(2t^2-)-2=0

We get rid of parentheses

-2t^2+(+1/t)^2-2+=0

We multiply all the terms by the denominator


-2t^2*t)^2+(-2*t)^2+()*t)^2+1=0

We add all the numbers together, and all the variables

-2t^2*t)^2+(-2t)^2+()*t)^2+1=0

Wy multiply elements

-2t^3-2t)^2+()*t)^2+1=0

We do not support etpression: t^3

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